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0=320x-6000-x^2
We move all terms to the left:
0-(320x-6000-x^2)=0
We add all the numbers together, and all the variables
-(320x-6000-x^2)=0
We get rid of parentheses
x^2-320x+6000=0
a = 1; b = -320; c = +6000;
Δ = b2-4ac
Δ = -3202-4·1·6000
Δ = 78400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{78400}=280$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-320)-280}{2*1}=\frac{40}{2} =20 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-320)+280}{2*1}=\frac{600}{2} =300 $
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